How to use open file dialog for open a any file in our application
Today i tell how to use open file dialog in our application to open a text file ......
before you use openfiledialog in your application you put button and text box
You right following code in button click event..
OpenFileDialog OS = new OpenFileDialog();
OS.ShowDialog();
FileStream fs = new FileStream(OS.FileName, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
StreamReader sr = new StreamReader(fs);
sr.BaseStream.Seek(0, SeekOrigin.Begin);
textBox1.Text = sr.ReadToEnd();
sr.Close();
fs.Close();
OS.ShowDialog();
FileStream fs = new FileStream(OS.FileName, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
StreamReader sr = new StreamReader(fs);
sr.BaseStream.Seek(0, SeekOrigin.Begin);
textBox1.Text = sr.ReadToEnd();
sr.Close();
fs.Close();
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